() (called unit) can be returned instead.;. Each expression in the sequence is evaluated in left-to-right order, but the value of the sequence is only the value of the rightmost expression.let <*identifier*> <*pattern_1*> ... <*pattern_n*> = <*expression1*> in <*expression2*>^)print_string : string -> unitstring_of_int : int -> stringstring_of_float : float -> stringThere are two infixed operators,
==and!=and one prefixed operator,!, which look familiar
let add_three x y z = x + y + z;; closure = <x -> fun y -> (fun z -> x + y + z), \rho >
2 + 3;; (* expression *)
3 < 2;; (* declaration *)
(* Sequencing Expressions and Declarations *)
"Hi there";; (* has type string *)
print_string "Hello world\n";; (* has type unit *)
(print_string "Bye\n"; 25);; (* Sequence of exp *)
(* Declarations *)
let test = 3 < 2;; (* declaration *)
let a = 1 let b = a + 4;; (* Sequence of dec *)
(* New Bindings Hide Old *)
let test = 3.7;;
(* Local let binding. **Global b is still 5.** *)
let b = 5 * 4 in 2 * b;;
let c =
let b = a + a
in b * b;;
b;;
(* Booleans (aka Truth Values) *)
true;;
false;;
if b > a then 25 else 0;;
(* Booleans *)
3 > 1 && 4 > 6;;
3 > 1 || 4 > 6;;
(print_string "Hi\n"; 3 > 1) || 4 > 6;;
3 > 1 || (print_string "Bye\n"; 4 > 6);;
not (4 > 6);;
(* Tuples *)
let s = (5,"hi",3.2);;
let (a,b,c) = s;;
let x = 2, 9.3;; (* tuples don't require parens in Ocaml *)
(* Tuples *)
let d = ((1,4,62),("bye",15),73.95);;
let (p,(st,_),_) = d;;
(* Functions *)
let plus_two n = n + 2;;
plus_two 17;;
fun n -> n + 2;;
(fun n -> n + 2) 17;;
let plus_two n = n + 2;;
plus_two 17;;
let plus_two = fun n -> n + 2;;
plus_two 14;;
(* Using a nameless function *)
(fun x -> x * 3) 5;; (* An application *)
((fun y -> y +. 2.0), (fun z -> z * 3));; (* As data *)
(* Values fixed at declaration time *)
let x = 12;;
let plus_x y = y + x;;
plus_x 3;;
(* Values fixed at declaration time *)
let x = 7;; (* Redecaration, Not an update *)
plus_x 3;;
(* Fuctions with more than one argument *)
let add_three x y z = x + y + z;;
let t = add_three 6 3 2;;
(* Partial application of functions *)
let h = add_three 5 4;;
h 3;;
h 7;;
(* Functions as arguments and results *)
let thrice f x = f (f (f x));;
let g = thrice plus_two;;
g 4;;
thrice (fun s -> "Hi! " ^ s) "Good-bye!";;
(* Recursive Functions *)
let rec factorial n =
if n = 0 then 1 else n * factorial (n - 1);;
factorial 5;;
(* better *)
let rec factorial n =
match n
with 0 -> 1
| _ -> n * factorial (n - 1);;
factorial 5;;
(* rec is needed for recursive function declarations *)
(* More on this later *)
(* Tuples *)
let fst_of_3 (x,_,_) = x;;
s;;
fst_of_3 s;;
fst_of_3 d;;
(* Curried vs Uncurried *)
let add_triple (u,v,w) = u + v + w;;
add_triple (6,3,2);;
add_triple 5 4;;
fun x -> add_triple (5,4,x);;
(* Match Expression *)
let triple_to_pair triple =
match triple
with (0, x, y) -> (x, y)
| (x, 0, y) -> (x, y)
| (x, y, 0) -> (x, y)
| (x, y, _) -> (x, y);;
(* Recursive Types - Lists *)
let fib5 = [8;5;3;2;1;1];;
let fib6 = 13 :: fib5;;
(8::5::3::2::1::1::[]) = fib5;;
fib5 @ fib6;;
(* Lists are Homogenous *)
let bad_list = [1; 3.2; 7];;
(* Functions Over Lists *)
let rec double_up list =
match list
with [] -> [] (* pattern before ->, expression after *)
| (x :: xs) -> (x :: x :: double_up xs);;
let fib5_2 = double_up fib5;;
(* Functions Over Lists *)
let silly = double_up ["hi"; "there"];;
let rec poor_rev list =
match list
with [] -> []
| (x::xs) -> poor_rev xs @ [x];;
poor_rev silly;;
(* Functions Over Lists *)
let rec map f list =
match list
with [] -> []
| (h::t) -> (f h) :: (map f t);;
map plus_two fib5;;
map (fun x -> x - 1) fib6;;
(* Iterating over lists *)
let rec fold_left f a list =
match list
with [] -> a
| (x :: xs) -> fold_left f (f a x) xs;;
fold_left
(fun () -> print_string)
()
["hi"; "there"];;
let rec fold_right f list b =
match list
with [] -> b
| (x :: xs) -> f x (fold_right f xs b);;
fold_right
(fun s -> fun () -> print_string s)
["hi"; "there"]
();;